What Happens When You Do A Burnout In An Open-Diff Car With Torque Vectoring?

Our V6-powered Jaguar XE S long-term test car doesn't have a limited-slip differential, but it does have torque vectoring by braking. So when you do a burnout, what happens? We found out...
Remote video URL

Since taking delivery of our Jaguar XE S longtermer, we’ve been intrigued by its drivetrain setup. It does without a limited-slip differential, but you do get torque vectoring by braking. This is supposed to act like an LSD, by applying small amounts of braking to alter the speeds of each of the rear wheels.

So, you shouldn’t get one wheel spinning up madly on its own, otherwise affectionately known as one tyre fire. To test just how effective it is, we thought we’d do the mature thing and perform a ruddy great burnout.

As you can see, it does ‘lock’ the wheels as an LSD would and rather nicely smokes both rear tyres (sorry, Jaguar…), but how well does it do some equally mature skids? Once you push past the initial understeer the XE S will happily shake its rear end about, but in our little test, the 335bhp Jaguar seemed very keen to light up just one wheel. So, the vectoring system can mimic an LSD, but not under every situation.

As to how it would perform when doing proper, full-on powerslides, we’re not yet sure. If we get the chance to try it out, you’ll be the first to know…

Comments

Anonymous

why did they actually not just put a real lsd??

03/10/2016 - 02:23 |
0 | 0
Ryan Fanberg

In reply to by Anonymous (not verified)

Manufactures make vehicles as cheap as they can. This is an entry level performance model. No reason to put one in,

03/10/2016 - 02:53 |
2 | 0
Anonymous

Funny, Ford Fiesta has Torque Vectoring and in the wet it will spin both front wheels that is with E-brake on haha !! Better then nothing at all! 👍🏽

03/15/2016 - 02:50 |
0 | 0

Topics

Manufacturers

Sponsored Posts